CSEC ADDITIONAL MATHEMATICS · EXAM PREPARATION · LESSON E5

Paper 032 Practice: Optimisation and Coordinate-Geometry Models

Two more 30-mark Paper 032 style questions with tagged marks — a calculus optimisation of a cylindrical can, and a lighthouse problem using a circle, a line and the discriminant.

Papers 1, 2 and 3Paper 032≈ 55 min
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

4 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON E5 · EXPLAINER

Paper 032 Practice: Optimisation and Coordinate-Geometry Models

A can that uses the least metal. A ship whose path just touches a lighthouse’s range. Two real situations, two full 30-mark practice questions.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Cylinder

V = πr²h; S = 2πr² + 2πrh; minimum S for fixed V when h = 2r.

Optimisation

One variable → dS/dr = 0 → second derivative → answer with units.

Comparison

Percentage more = (b − a)/a × 100.

Circle

x² + y² = r²; line + circle → quadratic → discriminant.

Tangent

Discriminant zero; path just touches.

Chord length

Distance between the intersection points.

Distance from O to a line

Perpendicular from O: gradient −1/m.

Reasoning

Quote numbers when recommending.

EXAM TIPS & COMMON MISTAKES

  • Make a single-variable function before differentiating.
  • Show S″ > 0 to justify a minimum — it is a reasoning mark.
  • Use the discriminant for “just touches” and “does not reach”.
  • End each model with a recommendation and a limitation.
Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

Paper 032 style

1. A cylinder has volume 500 cm³. Its height in terms of r is

Answer: A. h = V/(πr²).
Paper 032 style

2. The surface area of the closed cylinder of volume 500 cm³ is S =

Answer: B. 2πr² + 2πr(500/πr²).
Paper 032 style

3. dS/dr = 4πr − 1000/r² = 0 gives r³ equal to

Answer: C. 4πr³ = 1000.
Paper 032 style

4. The minimum surface area of the can is closest to

Answer: D. 348.7.
Paper 032 style

5. A ship’s path 3x − 4y = 40 meets the circle x² + y² = 100 at x equal to

Answer: A. 25x² − 240x = 0.
Paper 032 style

6. The length of the chord from (0, −10) to (9.6, −2.8) is

Answer: B. √(92.16 + 51.84) = 12.
Paper 032 style

7. A line meets a circle with discriminant 0. The line is

Answer: C. Repeated root.
Paper 032 style

8. A ship travels 12 km in range at 24 km/h. The time in range is

Answer: D. 12/24 h.
Step 4 · Apply

Mock paper — self-marked

Write full answers, then reveal the mark scheme and tick the points you earned (60 marks in total). Show all your working — method marks count. Your answers are saved on this device.

Paper 032 style · Optimisation (30 marks; [CK] 9, [AK] 12, [R] 9)

Question 1 [30 marks]

A company makes closed cylindrical cans of volume 500 cm³. Let the radius be r cm and the height h cm. A calculator may be used.

(a) (a) Write an expression for h in terms of r. [2]

MARK SCHEME — (a) (max 2)

(b) (b) Show that the total surface area is S = 2πr² + 1000/r. [3]

MARK SCHEME — (b) (max 3)

(c) (c) Find dS/dr. [2]

MARK SCHEME — (c) (max 2)

(d) (d) Find the value of r for which S is a minimum, giving your answer to 3 significant figures. [3]

MARK SCHEME — (d) (max 3)

(e) (e) Show that this value of r gives a minimum. [2]

MARK SCHEME — (e) (max 2)

(f) (f) Calculate the corresponding height and the minimum surface area. [3]

MARK SCHEME — (f) (max 3)

(g) (g) Show that h = 2r at the minimum. [2]

MARK SCHEME — (g) (max 2)

(h) (h) A tall thin can has r = 3 cm. Calculate its surface area and the percentage more metal it uses. [4]

MARK SCHEME — (h) (max 4)

(i) (i) Metal costs $0.002 per cm². Find the metal cost of one minimum can and of 10 000 minimum cans. [3]

MARK SCHEME — (i) (max 3)

(j) (j) Recommend the dimensions for the can and give ONE reason why the company may choose a different shape. [2]

MARK SCHEME — (j) (max 2)

(k) (k) State one limitation of this model. [1]

MARK SCHEME — (k) (max 1)

(l) (l) The company also considers an open-top can of the same volume. Write S in terms of r, find the radius that minimises S, and state how h compares with r. [3]

MARK SCHEME — (l) (max 3)

Paper 032 style · Coordinate geometry (30 marks; [CK] 9, [AK] 12, [R] 9)

Question 2 [30 marks]

A lighthouse is at the origin O. Its light can be seen up to 10 km from O. A ship sails along the straight line with equation 3x − 4y = 40 (distances in km).

(a) (a) Write the equation of the boundary of the lighthouse’s range. [2]

MARK SCHEME — (a) (max 2)

(b) (b) Show that the ship’s path meets the boundary at (0, −10) and (9.6, −2.8). [5]

MARK SCHEME — (b) (max 5)

(c) (c) Calculate the distance the ship travels within range. [2]

MARK SCHEME — (c) (max 2)

(d) (d) The ship travels at 24 km/h. For how many minutes is it within range? [2]

MARK SCHEME — (d) (max 2)

(e) (e) Another path has equation 3x − 4y = c. Show that it is a tangent to the boundary when c = 50 (c > 0). [4]

MARK SCHEME — (e) (max 4)

(f) (f) Find the coordinates of the point of contact for c = 50. [3]

MARK SCHEME — (f) (max 3)

(g) (g) The captain wants to avoid being within range. State the condition on c for the path 3x − 4y = c (c > 0) to stay out of range and give a reason. [3]

MARK SCHEME — (g) (max 3)

(h) (h) Find the shortest distance from O to the path 3x − 4y = 40 and comment. [5]

MARK SCHEME — (h) (max 5)

(i) (i) State one assumption in this model. [1]

MARK SCHEME — (i) (max 1)

(j) (j) Write a short recommendation for the captain. [3]

MARK SCHEME — (j) (max 3)

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Sources

Syllabus sources and past papers

Everything in this lesson is based on these parts of the CXC syllabus and papers.