CSEC ADDITIONAL MATHEMATICS · SECTION 2 · LESSON B7

Trigonometric Identities: Compound and Double Angle Formulae

The Pythagorean identity, tan θ = sin θ/cos θ, the compound-angle and double-angle formulae, exact values from them, and proving identities.

Coordinate Geometry, Vectors and TrigonometryS2 C.7S2 C.8S2 C.9S2 C.10S2 C.11≈ 50 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON B7 · EXPLAINER

Trigonometric Identities: Compound and Double Angle Formulae

sin(A + B) is not sin A + sin B — it has its own formula. Learn the handful of identities and you can simplify, evaluate and prove almost anything in trigonometry.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Pythagorean

cos²θ + sin²θ ≡ 1; 1 + tan²θ ≡ sec²θ.

Tangent

tan θ ≡ sin θ/cos θ.

Compound angles

sin(A ± B) = sinAcosB ± cosAsinB; cos(A ± B) = cosAcosB ∓ sinAsinB; tan(A ± B) = (tanA ± tanB)/(1 ∓ tanAtanB).

Double angle

sin 2A = 2sinAcosA; cos 2A = cos²A − sin²A = 2cos²A − 1 = 1 − 2sin²A; tan 2A = 2tanA/(1 − tan²A).

Reverse use

Recognise sinAcosB − cosAsinB as sin(A − B).

Proofs

One side only; end exactly at the other side.

Exact values

75° = 45° + 30°; 15° = 45° − 30°.

Needed knowledge

You need not prove the compound-angle formulae.

EXAM TIPS & COMMON MISTAKES

  • cos(A + B) has a MINUS sign: cosAcosB − sinAsinB.
  • Choose the form of cos 2x that suits the problem (in terms of sin or cos only).
  • In proofs write each line as an equality starting from LHS and ending at RHS.
  • Use exact values: do not turn √2/2 into a decimal.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Additional Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

Adapted from CSEC P1 May/June 2024 (compound-angle item)

1. sin 50° cos 40° − cos 50° sin 40° is equal to

Answer: D. sin(50° − 40°).
Adapted from CSEC P1 May/June 2024 (double-angle item)

2. If sin x = s, then cos 2x is equal to

Answer: A. cos 2x = 1 − 2sin²x.
CSEC Paper 01 style · SO C.10

3. sin 2x is equal to

Answer: B. Double-angle formula.
CSEC Paper 01 style · SO C.9

4. The exact value of sin 75° is

Answer: C. sin(45° + 30°).
CSEC Paper 01 style · SO C.9

5. sin A = 3/5 and cos B = 5/13, with A and B acute. sin(A + B) is

Answer: D. (3/5)(5/13) + (4/5)(12/13) = 63/65.
CSEC Paper 01 style · SO C.10

6. If sin x = 3/5 and x is acute, cos 2x equals

Answer: A. 1 − 2(9/25).
CSEC Paper 01 style · SO C.11

7. Which expression is identical to (1 − cos 2x)/sin 2x?

Answer: B. 2sin²x/(2 sin x cos x).
CSEC Paper 01 style · SO C.9

8. If tan A = 1/2 and tan B = 1/3 then tan(A + B) equals

Answer: C. (5/6)/(1 − 1/6) = 1.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (24 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Section 2 (Trigonometric identities)

Question 1 [13 marks]

Answer all parts.

(a) Prove that (1 − cos 2x)/sin 2x ≡ tan x. [4]

MARK SCHEME — (a) (max 4)

(b) Given that sin A = 3/5 and cos B = 5/13, where A and B are acute angles, find the exact value of (i) sin(A + B), (ii) cos(A − B). [6]

MARK SCHEME — (b) (max 6)

(c) Find the exact value of cos 15°, using cos 15° = cos(45° − 30°). [3]

MARK SCHEME — (c) (max 3)

CSEC Paper 02 style · Section 2 (More identities)

Question 2 [11 marks]

Answer all parts.

(a) Prove that sin x/(1 − cos x) ≡ (1 + cos x)/sin x. [4]

MARK SCHEME — (a) (max 4)

(b) Given tan A = 1/2 and tan B = 1/3, show that A + B = 45°. [3]

MARK SCHEME — (b) (max 3)

(c) Given that cos x = 4/5 and x is acute, find the values of sin 2x, cos 2x and tan 2x. [4]

MARK SCHEME — (c) (max 4)

Your progress

Lesson readiness

0%
READY
Not started
Video watched (20%)0%
Multiple choice (40%)0%
Structured (40%)0%

Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.