CSEC PHYSICS · SECTION A · LESSON A10

Aristotle and Newton’s Three Laws of Motion

Why Aristotle’s “law of motion” was discredited, Newton’s three laws, F = ma, action and reaction, and applications such as seat belts, rockets, sprinklers and terminal velocity.

MechanicsA 4.3A 4.4A 4.5≈ 45 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON A10 · EXPLAINER

Aristotle and Newton’s Three Laws of Motion

Push a book across a table and it stops. Aristotle thought force is needed to keep things moving. Newton explained that the book stops only because friction acts on it.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Aristotle

Velocity ∝ force; discredited because friction was ignored.

Newton 1

A body stays at rest or at constant velocity unless a resultant force acts (inertia).

Newton 2

F = ma (resultant force); a ∝ F; a ∝ 1/m.

Newton 3

Equal and opposite forces, acting on DIFFERENT bodies.

Inertia

Resistance to change of motion; bigger mass, more inertia.

Newton

1 N = 1 kg m/s².

Terminal velocity

Resultant force zero: air resistance = weight.

Applications

Seat belts (N1), rockets and sprinklers (N3), trampolines (N3).

EXAM TIPS & COMMON MISTAKES

  • In F = ma, F is the RESULTANT force: subtract opposing forces first.
  • Third-law pairs act on different bodies. “Weight and the reaction of the table” are NOT a third-law pair.
  • Explain inertia by saying the body “continues in its state of rest or constant velocity”.
  • Terminal velocity: do not say “there are no forces” — say the forces are balanced.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Physics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

Syllabus A 4.4

1. Newton’s first law explains why

Answer: D. Passengers continue moving because of inertia.
Syllabus A 4.5

2. A resultant force of 12 N acts on a 3.0 kg mass. The acceleration is

Answer: A. a = F ÷ m = 12 ÷ 3.0 = 4.0 m/s².
Syllabus A 4.5

3. The same resultant force acts on two masses, 2 kg and 4 kg. Compared with the 2 kg mass, the acceleration of the 4 kg mass is

Answer: B. a ∝ 1/m.
Syllabus A 4.5

4. A rocket moves forward because

Answer: C. Newton’s third law.
Syllabus A 4.4

5. Which statement about Newton’s third law is correct?

Answer: D. The pair acts on different bodies.
Syllabus A 4.5

6. A parachutist falls at constant (terminal) velocity. The resultant force on the parachutist is

Answer: A. Air resistance equals weight, so forces balance.
Syllabus A 4.3

7. Aristotle’s idea that a force is needed to keep a body moving was discredited because it

Answer: B. Friction is the force that brings everyday objects to rest.
Syllabus A 4.5

8. A car of mass 1 000 kg has an engine force of 2 500 N and resistive forces of 500 N. Its acceleration is

Answer: C. Resultant 2 000 N; a = 2 000 ÷ 1 000 = 2.0 m/s².
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (15 marks in total). Show all your working — method marks count. Your answers are saved on this device.

Paper 2 style · Newton’s laws

Question 1 [15 marks]

A car of mass 1 500 kg travels along a straight level road. The engine produces a forward force of 4 000 N and the resistive forces total 1 000 N.

(a) (a) State Newton’s second law of motion. [2]

MARK SCHEME — (a) (max 2)

(b) (b) Calculate the resultant force on the car. [2]

MARK SCHEME — (b) (max 2)

(c) (c) Calculate the acceleration of the car. [3]

MARK SCHEME — (c) (max 3)

(d) (d) The car reaches a speed at which the resistive forces equal the engine force. Describe its motion afterwards, and name this law. [2]

MARK SCHEME — (d) (max 2)

(e) (e) State Newton’s third law and give one example. [3]

MARK SCHEME — (e) (max 3)

(f) (f) Explain why a passenger without a seat belt moves forward when the car brakes suddenly. [3]

MARK SCHEME — (f) (max 3)

Your progress

Lesson readiness

0%
READY
Not started
Video watched (20%)0%
Multiple choice (40%)0%
Structured (40%)0%

Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.