CSEC MATHEMATICS · MODULE 2 · LESSON B13

Vectors: Column Vectors, Algebra and Geometry

Vectors and scalars, column vector notation, adding, subtracting and multiplying by a scalar, the triangle and parallelogram laws, and parallel vectors.

Intermediate Secondary Level MathematicsM2 5.1M2 5.2≈ 40 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON B13 · EXPLAINER

Vectors: Column Vectors, Algebra and Geometry

A plane flies 300 km/h north-east into a westerly wind. Speed alone is not enough — you need direction too. That is a vector.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Explore in 3D

Vectors

Change the components and see a + b.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Vector vs scalar

Vector: magnitude + direction. Scalar: magnitude only.

Notation

AB (arrow), a (bold or underlined), column form xy.

Magnitude

|a| = √(x² + y²).

Equal / negative / parallel

Equal: same magnitude and direction. −a reverses direction. ka is parallel to a.

Operations

Add, subtract and multiply by a scalar component by component.

Triangle law

AB + BC = AC. AB = OB − OA = b − a.

Parallelogram law

If OACB is a parallelogram with OA = a and OB = b, then OC = a + b.

Collinear

If AB = k BC then A, B, C are on a straight line.

EXAM TIPS & COMMON MISTAKES

  • Direction matters: AB = −BA. Check which way the arrow goes before adding.
  • Write the path you take (e.g. AB = AO + OB) before simplifying — it earns the method mark.
  • Give the final vector in its simplest form in terms of a and b.
  • Parallel means “a scalar multiple of”: (6, −4) and (3, −2) are parallel since (6, −4) = 2(3, −2).
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

CSEC Paper 01 style · SO 5.1

1. The magnitude of the vector 34 is

Answer: B. √(3² + 4²) = √25 = 5.
CSEC Paper 01 style · SO 5.2

2. If a = 32 and b = −14, then a + b is

Answer: B. (3 − 1, 2 + 4) = (2, 6).
CSEC Paper 01 style · SO 5.2

3. If a = 32 and b = −14, then 2a − b is

Answer: C. (6 + 1, 4 − 4) = (7, 0).
CSEC Paper 01 style · SO 5.2

4. OA = a and OB = b. The vector AB is

Answer: D. AB = AO + OB = −a + b = b − a.
CSEC Paper 01 style · SO 5.1

5. Which vector is parallel to 6−4?

Answer: A. (6, −4) = 2 × (3, −2).
CSEC Paper 01 style · SO 5.1

6. If p = 3−2, then −p is

Answer: B. Reverse every sign: (−3, 2).
CSEC Paper 01 style · SO 5.2

7. M is the midpoint of AB, where OA = a and OB = b. The vector OM is

Answer: C. OM = OA + ½AB = a + ½(b − a) = ½(a + b).
CSEC Paper 01 style · SO 5.2

8. OACB is a parallelogram with OA = a and OB = b. The vector OC is

Answer: D. The diagonal of the parallelogram: OC = OA + AC = a + b.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (16 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Module 2 (Vectors)

Question 1 [7 marks]

p = 4-3 and q = -12.

(a) Write p + q as a column vector. [1]

MARK SCHEME — (a) (max 1)

(b) Express 2p − 3q as a column vector. [2]

MARK SCHEME — (b) (max 2)

(c) Calculate |p|. [2]

MARK SCHEME — (c) (max 2)

(d) Write down a vector which is parallel to p and has magnitude 10. [2]

MARK SCHEME — (d) (max 2)

CSEC Paper 02 style · Module 2 (Vector geometry)

Question 2 [9 marks]

In triangle OAB, OA = a and OB = b. M is the midpoint of AB. N is the point on OB such that ON = ⅔ OB.

(a) Express AB in terms of a and b. [1]

MARK SCHEME — (a) (max 1)

(b) Express OM in terms of a and b, giving your answer in its simplest form. [3]

MARK SCHEME — (b) (max 3)

(c) Express AN in terms of a and b. [2]

MARK SCHEME — (c) (max 2)

(d) Show that MN = ⅙b − ½a. [3]

MARK SCHEME — (d) (max 3)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.