CSEC MATHEMATICS · MODULE 2 · LESSON B12

Pythagoras’ Theorem and the Trigonometric Ratios

Pythagoras’ theorem, sine, cosine and tangent in right-angled triangles, finding sides and angles, and angles of elevation and depression.

Intermediate Secondary Level MathematicsM2 4.7M2 4.8M2 4.9M2 4.10≈ 45 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON B12 · EXPLAINER

Pythagoras’ Theorem and the Trigonometric Ratios

How tall is that building without climbing it? Measure the distance and the angle, and one button on your calculator does the rest.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Explore in 3D

Pythagoras and trigonometry

See the squares on the sides, then the trigonometric ratios.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Pythagoras

c² = a² + b² (c = hypotenuse). Hypotenuse: add squares. Shorter side: subtract.

Pythagorean triples

3-4-5; 5-12-13; 8-15-17; 7-24-25 and multiples.

Sides

Hypotenuse opposite the right angle; opposite and adjacent relative to the angle.

Ratios

sin θ = O/H; cos θ = A/H; tan θ = O/A (SOH CAH TOA).

Finding a side

Choose the ratio with the known and unknown sides; rearrange; use degree mode.

Finding an angle

θ = sin⁻¹, cos⁻¹ or tan⁻¹ of the ratio.

Elevation / depression

Measured from the horizontal; equal alternate angles. Add the height of the observer’s eyes.

Accuracy

3 significant figures for lengths, 1 decimal place for angles, unless told otherwise.

EXAM TIPS & COMMON MISTAKES

  • Label O, A, H on a sketch before choosing sin, cos or tan.
  • Check the calculator is in DEGREES (D or DEG on the screen).
  • Height problems: add the observer’s eye height to the calculated height — a classic lost mark.
  • Check your answer is sensible: the hypotenuse is always the longest side.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

CSEC Paper 01 style · SO 4.7

1. The hypotenuse of a right-angled triangle with the other two sides 6 cm and 8 cm is

Answer: B. √(36 + 64) = 10.
CSEC Paper 01 style · SO 4.7

2. The hypotenuse of a right-angled triangle is 13 cm and one side is 5 cm. The other side is

Answer: C. √(169 − 25) = 12.
CSEC Paper 01 style · SO 4.8

3. In a right-angled triangle, sin θ is equal to

Answer: D. SOH: sine = opposite ÷ hypotenuse.
CSEC Paper 01 style · SO 4.10

4. In a right-angled triangle the hypotenuse is 12 cm and an angle is 35°. The side opposite the 35° angle is

Answer: A. sin 35° = opposite ÷ 12.
CSEC Paper 01 style · SO 4.10

5. If tan θ = 5/12 then θ is closest to

Answer: B. tan⁻¹(5/12) = 22.6°.
Adapted from CSEC P1 May/June 2024 (angle of elevation item)

6. A surveyor sets up his instrument 1.6 m above the ground, 12 m from the foot of a building, and records an angle of elevation of 40° to the top. The height of the building is

Answer: C. Height above eye level = 12 tan 40°; add the 1.6 m.
CSEC Paper 01 style · SO 4.10

7. From the top of a 50 m lighthouse the angle of depression of a boat is 25°. The distance of the boat from the foot of the lighthouse is

Answer: D. tan 25° = 50/d → d = 50 ÷ tan 25°.
CSEC Paper 01 style · SO 4.7

8. A ladder 5 m long leans against a wall with its foot 3 m from the wall. How high up the wall does it reach?

Answer: A. √(25 − 9) = 4.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (16 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Module 2 (Right-angled triangles)

Question 1 [8 marks]

In triangle ABC, angle B = 90°, AB = 9 cm and BC = 12 cm.

(a) Calculate the length of AC. [2]

MARK SCHEME — (a) (max 2)

(b) Calculate the size of angle BAC, correct to 1 decimal place. [3]

MARK SCHEME — (b) (max 3)

(c) Hence state the size of angle ACB and calculate the area of the triangle. [3]

MARK SCHEME — (c) (max 3)

CSEC Paper 02 style · Module 2 (Elevation and depression)

Question 2 [8 marks]

A student whose eyes are 1.5 m above the ground stands 20 m from the foot of a tree. The angle of elevation of the top of the tree is 35°.

(a) Draw a sketch showing the information (right-angled triangle with 20 m, 35° and the unknown height marked). [2]

MARK SCHEME — (a) (max 2)

(b) Calculate the height of the tree to 1 decimal place. [3]

MARK SCHEME — (b) (max 3)

(c) From the top of a 50 m cliff the angle of depression of a boat is 25°. Calculate the horizontal distance of the boat from the foot of the cliff, to 1 decimal place. [3]

MARK SCHEME — (c) (max 3)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.