CSEC MATHEMATICS · MODULE 1 · LESSON A10

Perimeter, Area, Circles, Arcs and Sectors

Perimeter and area of polygons and circles, arc length and the area of a sector, estimating area, and compound shapes.

Fundamentals of Secondary Level MathematicsM1 4.1M1 4.3M1 4.4M1 4.5M1 4.6M1 4.7≈ 40 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON A10 · EXPLAINER

Perimeter, Area, Circles, Arcs and Sectors

Fencing a yard, tiling a floor, painting a wall, cutting a pizza — measurement is where maths meets the real world, and it fills a whole section of Paper 02.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Perimeter

Add all outside edges; for circles C = 2πr.

Area formulae

Rectangle lw; triangle ½bh; parallelogram bh; trapezium ½(a + b)h; circle πr². (The trapezium, circle and triangle formulae are on the exam formula sheet.)

Arc and sector

Arc = θ/360 × 2πr. Sector area = θ/360 × πr². Perimeter of sector = arc + 2r.

Compound shapes

Split into simple shapes; add areas or subtract holes; perimeter uses outside edges only.

Estimating

Whole squares + half-or-more squares, × area of one square.

Units

Area in square units (cm², m²). 1 m² = 10 000 cm².

Working backwards

To find a missing height or radius, substitute known values and solve the equation.

π

Use the value given: 22/7, 3.14 or the calculator key. Leave in terms of π if asked.

EXAM TIPS & COMMON MISTAKES

  • Use the PERPENDICULAR height for triangles and trapezia — not the slanted side.
  • Square the radius BEFORE multiplying by π: πr² means π × (r × r).
  • The perimeter of a sector includes the two radii — a classic lost mark.
  • Show the formula, the substitution and then the answer with units. The CXC mark scheme awards a mark for the substitution.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

CSEC Paper 01 style · SO 4.3

1. Using π = 22/7, the circumference of a circle of radius 7 cm is

Answer: B. C = 2πr = 2 × 22/7 × 7 = 44 cm.
Adapted from CSEC P1 May/June 2024 (square item)

2. The perimeter of a square is 48 cm. What is its area, in cm²?

Answer: D. Side = 12 cm; area = 12² = 144 cm².
Based on CSEC P1 May/June 2024 (trapezium height item)

3. A trapezium has parallel sides of 9 cm and 17 cm and an area of 65 cm². Its height is

Answer: B. 65 = ½ × 26 × h → h = 5.
CSEC Paper 01 style · SO 4.6

4. The area of a circle of radius 10 cm, in terms of π, is

Answer: C. A = πr² = π × 100.
Based on CSEC P1 May/June 2024 (arc length item)

5. A sector of a circle has angle 60° and radius r. The length of its arc is

Answer: C. Arc = 60/360 × 2πr = πr/3.
CSEC Paper 01 style · SO 4.7

6. The area of a sector of angle 90° in a circle of radius 8 cm is

Answer: D. ¼ × π × 64 = 16π.
Adapted from CSEC P1 May/June 2024 (rectangle scaling item)

7. The area of a rectangle is 40 cm². If the length is multiplied by 4 and the width is halved, the new area is

Answer: A. Area × 4 × ½ = 2 × 40 = 80 cm².
Adapted from CSEC P1 May/June 2024 (compound shape item)

8. A compound shape is a square of side 5 cm with a triangle on top. The total area is 35 cm². The height of the triangle is

Answer: B. Triangle area = 35 − 25 = 10 = ½ × 5 × h → h = 4.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (15 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Module 1 (Sectors)

Question 1 [7 marks]

A piece of wire, 64 cm long, is bent to form the boundary of a sector of a circle of radius 21 cm. Use π = 22/7.

(a) Calculate the length of the arc of the sector. [2]

MARK SCHEME — (a) (max 2)

(b) Show that the angle of the sector is 60°. [3]

MARK SCHEME — (b) (max 3)

(c) Calculate the area enclosed by the wire. [2]

MARK SCHEME — (c) (max 2)

CSEC Paper 02 style · Module 1 (Compound shapes)

Question 2 [8 marks]

A window is made of a rectangle 1.2 m wide and 0.8 m high with a semicircle of diameter 1.2 m on top. Use π = 3.14.

(a) Calculate the area of the window. [3]

MARK SCHEME — (a) (max 3)

(b) Calculate the perimeter of the window. [3]

MARK SCHEME — (b) (max 3)

(c) Glass costs $120 per square metre. Find the cost of the glass for the window, to the nearest dollar. [2]

MARK SCHEME — (c) (max 2)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.