CSEC ADDITIONAL MATHEMATICS · SECTION 3 · LESSON C8

Volumes of Revolution and Kinematics by Integration

Volumes of solids formed by rotating a region about the x-axis, and finding velocity from acceleration and displacement from velocity.

Introductory CalculusS3 B.9≈ 50 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON C8 · EXPLAINER

Volumes of Revolution and Kinematics by Integration

Rotate a flat region about an axis and you sweep out a solid — a cone, a bowl, a vase. Integration finds its volume. Run the same machinery on acceleration and you get velocity and distance.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Explore in 3D

Volumes of revolution

Rotate a curve about the x-axis in 3D.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Volume of revolution

V = π∫ₐᵇ y² dx (about the x-axis; first-quadrant region).

Square

Expand y² fully before integrating.

Velocity

v = ∫ a dt + C (use initial velocity).

Displacement

s = ∫ v dt + D (use initial position).

Displacement in an interval

∫ₜ₁ᵗ² v dt.

Total distance

Split where v = 0 and add absolute values.

Variable motion

SUVAT not valid unless a is constant.

Checking

Differentiate your s to recover v and a.

EXAM TIPS & COMMON MISTAKES

  • Square the WHOLE function: (x + 1)² = x² + 2x + 1.
  • Leave the answer in terms of π unless a decimal is requested.
  • Use the initial conditions to find each constant of integration.
  • For total distance check whether v changes sign in the interval.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Additional Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

CSEC Paper 01 style · SO B.9

1. The region under y = x from x = 0 to x = 3 is rotated about the x-axis. The volume formed is

Answer: A. π∫₀³ x² dx = 9π.
CSEC Paper 01 style · SO B.9

2. The volume formed when y = x² from x = 0 to x = 1 is rotated about the x-axis is

Answer: B. π∫ x⁴ dx.
CSEC Paper 01 style · SO B.9

3. The volume of revolution of y = x + 1 from x = 0 to x = 2 about the x-axis is

Answer: C. π[(x + 1)³/3]₀².
CSEC Paper 01 style · SO B.9

4. If a = 6t − 4 and v = 3 when t = 0, then v is

Answer: A. v = 3t² − 4t + C, C = 3.
CSEC Paper 01 style · SO B.9

5. Given v = 3t² − 4t + 3 and s = 0 when t = 0, s is

Answer: D. Integrate.
CSEC Paper 01 style · SO B.9

6. The distance travelled between t = 2 and t = 3 when v = 3t² − 4t + 3 is

Answer: A. [t³ − 2t² + 3t]₂³ = 18 − 6.
CSEC Paper 01 style · SO B.9

7. A particle has v = 6t − 3t² and s = 0 at t = 0. It is at rest at t = 2 where s equals

Answer: B. s = 3t² − t³ = 12 − 8.
CSEC Paper 01 style · SO B.9

8. If an object has variable acceleration, the formula v = u + at

Answer: B. It requires constant acceleration.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (24 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Section 3 (Volumes of revolution)

Question 1 [13 marks]

Answer all parts, leaving answers in terms of π.

(a) The region enclosed by y = x + 2, the x-axis, the y-axis and the line x = 2 is rotated through 360° about the x-axis. Calculate the volume of the solid formed. [5]

MARK SCHEME — (a) (max 5)

(b) Show that the region enclosed by y = x, the x-axis and x = 3, rotated about the x-axis, gives 9π, and verify with the volume of a cone. [4]

MARK SCHEME — (b) (max 4)

(c) Find the volume formed by rotating the region under y = x² + 1 from x = 0 to x = 1 about the x-axis. [4]

MARK SCHEME — (c) (max 4)

CSEC Paper 02 style · Section 3 (Kinematics by integration)

Question 2 [11 marks]

A particle moves in a straight line. Its acceleration at time t seconds is a = 6t − 4 m/s². When t = 0 its velocity is 3 m/s and its displacement is 0.

(a) Find expressions for the velocity and displacement at time t. [5]

MARK SCHEME — (a) (max 5)

(b) Show that the particle is never at rest. [2]

MARK SCHEME — (b) (max 2)

(c) Find the distance travelled by the particle in the third second (between t = 2 and t = 3). [3]

MARK SCHEME — (c) (max 3)

(d) Find the acceleration when t = 2. [1]

MARK SCHEME — (d) (max 1)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.