CSEC PHYSICS · SECTION A · LESSON A6

Moments and the Principle of Moments

The turning effect of a force, calculating moments (force × perpendicular distance), applying the principle of moments to balanced beams and see-saws, and the action of levers.

MechanicsA 3.7A 3.8A 3.9A 3.10≈ 40 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON A6 · EXPLAINER

Moments and the Principle of Moments

A long spanner loosens a stubborn nut that a short one cannot. The longer the distance from the pivot, the greater the turning effect.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Explore in 3D

Moments in 3D

Move the masses along the beam until the moments balance.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Moment

M = F × d, with d the PERPENDICULAR distance from the pivot; unit N m.

Turning effect

Increase with a bigger force or a longer perpendicular distance.

Equilibrium

No resultant force and no resultant moment.

Principle of moments

Clockwise moments = anticlockwise moments about any point.

Reaction

Upward forces = downward forces.

Uniform beam

Its weight acts at its centre.

Levers

Fulcrum, effort, load; a long effort arm needs a small effort.

Units

N m is not J: moment is a turning effect; energy is force × distance moved.

EXAM TIPS & COMMON MISTAKES

  • Always measure the distance from the pivot to the line of action of the force.
  • Do not forget the weight of the beam (at its centre) if it is uniform and the question gives its mass or weight.
  • Write “clockwise = anticlockwise” and substitute: it earns the method mark.
  • Check with the reaction: upward force = sum of the downward forces.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Physics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

Syllabus A 3.8

1. The moment of a force is calculated using

Answer: D. M = F × d.
Syllabus A 3.8

2. The unit of a moment is the

Answer: A. Force (N) × distance (m).
Syllabus A 3.8

3. A force of 15 N acts at a perpendicular distance of 0.20 m from a pivot. The moment is

Answer: B. 15 × 0.20 = 3.0 N m.
Syllabus A 3.9

4. A uniform beam is balanced when

Answer: C. The principle of moments.
Syllabus A 3.9

5. On a see-saw a 300 N child sits 2.0 m from the pivot. A 400 N adult balances it. The adult sits

Answer: D. 400 × d = 300 × 2.0 so d = 1.5 m.
Syllabus A 3.10

6. In a claw hammer used to remove a nail, the fulcrum is

Answer: A. The hammer turns about its contact with the surface.
Syllabus A 3.7

7. A spanner with a longer handle makes it easier to turn a nut because it

Answer: B. Bigger distance gives a bigger moment for the same force.
Syllabus A 3.9

8. A uniform metre rule is pivoted at its centre. A 3.0 N weight is hung at the 20 cm mark. What weight at the 100 cm mark balances it?

Answer: C. 3.0 × 0.30 = W × 0.50 gives W = 1.8 N.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (15 marks in total). Show all your working — method marks count. Your answers are saved on this device.

Paper 2 style · Moments

Question 1 [15 marks]

A uniform metre rule of weight 1.0 N is pivoted at its centre (50 cm mark).

(a) (a) State the principle of moments. [2]

MARK SCHEME — (a) (max 2)

(b) (b) A 4.0 N weight is hung at the 20 cm mark. Calculate its moment about the pivot. [3]

MARK SCHEME — (b) (max 3)

(c) (c) A second weight W is hung at the 80 cm mark to balance the rule. Calculate W. [3]

MARK SCHEME — (c) (max 3)

(d) (d) Calculate the upward force of the pivot on the rule. [2]

MARK SCHEME — (d) (max 2)

(e) (e) State the effect on the balance if the 4.0 N weight is moved to the 10 cm mark. [2]

MARK SCHEME — (e) (max 2)

(f) (f) Identify the effort, load and fulcrum when a wheelbarrow is used to carry soil. [3]

MARK SCHEME — (f) (max 3)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.