CSEC MATHEMATICS · MODULE 3 · LESSON C1

Grouped Data: Class Features, Histograms and Frequency Polygons

Grouping data into classes, class limits, boundaries, midpoints and width, histograms with equal bars, frequency polygons, and estimating the mean, modal class and median class.

Higher Concepts in Secondary Level MathematicsM3 1.1M3 1.2M3 1.3M3 1.4M3 1.5≈ 45 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON C1 · EXPLAINER

Grouped Data: Class Features, Histograms and Frequency Polygons

When there are 200 different heights, a list is useless. Group them into classes and a pattern appears at once — and you can still estimate the mean.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Class limits

The stated ends of a class, e.g. 140–149.

Class boundaries

Halfway between the upper limit of one class and the lower limit of the next: 139.5 and 149.5.

Class width & midpoint

Width = upper boundary − lower boundary. Midpoint = (lower limit + upper limit) ÷ 2.

Histogram

Equal widths: bars touch, drawn between boundaries, height = frequency.

Frequency polygon

Plot (midpoint, frequency); join with straight lines; close at both ends with f = 0.

Estimated mean

Σfx ÷ Σf with x = class midpoint.

Modal class

Highest frequency.

Median class

Class that contains the (n/2)-th value (use cumulative frequency).

EXAM TIPS & COMMON MISTAKES

  • Histogram bars go between BOUNDARIES — 139.5 to 149.5 — never between limits.
  • The mean from grouped data is always an estimate: use that word in your answer.
  • Use the midpoint of EACH class for fx — recompute each, do not guess.
  • Show Σf and Σfx totals at the bottom of your table; check Σf equals the sample size.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

CSEC Paper 01 style · SO 1.2

1. For the class 20–29 (lengths measured to the nearest cm), the class boundaries are

Answer: A. Boundaries lie halfway between 19 and 20, and between 29 and 30.
CSEC Paper 01 style · SO 1.2

2. The midpoint of the class 20–29 is

Answer: B. (20 + 29)/2 = 24.5.
CSEC Paper 01 style · SO 1.2

3. A frequency table has the classes 140–149, 150–159, 160–169 and so on. The class width is

Answer: C. Boundaries 139.5 and 149.5 differ by 10.
CSEC Paper 01 style · SO 1.3

4. In a histogram with equal class widths, the height of a bar represents the

Answer: B. With equal widths, the height is proportional to the frequency, so it shows the frequency.
CSEC Paper 01 style · SO 1.3

5. A frequency polygon is drawn by plotting the frequencies against the

Answer: C. Points are plotted at the midpoints.
Adapted from CSEC P1 May/June 2024 (grouped frequency item)

6. The table shows the average mass, in kg, of a group of children: 21–30 (28), 31–40 (34), 41–50 (12), 51–60 (38), 61–70 (20). The number of children with a mass of at least 41 kg is

Answer: C. 12 + 38 + 20 = 70.
Adapted from CSEC P1 May/June 2024 (modal class item)

7. In the same table, the lower boundary of the modal class is

Answer: C. Modal class 51–60 (frequency 38); lower boundary 50.5.
CSEC Paper 01 style · SO 1.4

8. From the heights table (6, 10, 14, 7, 3), the estimated mean height in cm is

Answer: B. Σfx = 6 490; Σf = 40; 6 490/40 = 162.25.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (20 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Module 3 (Grouped data)

Question 1 [11 marks]

The heights of 40 students are summarised in the table: 140–149 (6), 150–159 (10), 160–169 (14), 170–179 (7), 180–189 (3).

(a) State (i) the class boundaries and the class width of the third class, and (ii) its midpoint. [3]

MARK SCHEME — (a) (max 3)

(b) Calculate an estimate of the mean height, to 2 decimal places. [4]

MARK SCHEME — (b) (max 4)

(c) State the modal class and the class containing the median. [2]

MARK SCHEME — (c) (max 2)

(d) Estimate the percentage of students taller than 169.5 cm. [2]

MARK SCHEME — (d) (max 2)

CSEC Paper 02 style · Module 3 (Drawing diagrams)

Question 2 [9 marks]

Use the grouped data in the table above.

(a) On graph paper draw a histogram of the data. (Check: boundaries on the x-axis from 139.5 to 189.5, bars touching, heights 6, 10, 14, 7, 3, labelled axes with units, title.) [4]

MARK SCHEME — (a) (max 4)

(b) On the same graph or a new one, draw the frequency polygon. State which values you plot. [3]

MARK SCHEME — (b) (max 3)

(c) Explain why the mean calculated from grouped data is only an estimate. [2]

MARK SCHEME — (c) (max 2)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.