CSEC MATHEMATICS · MODULE 2 · LESSON B8

Relations and Functions: Notation, Composite and Inverse Functions

Domain, range and image, arrow diagrams and the vertical line test, functional notation, evaluating functions, composite functions and inverse functions.

Intermediate Secondary Level MathematicsM2 3.1M2 3.2M2 3.3M2 3.4M2 3.5M2 3.11M2 3.12M2 3.13M2 3.14≈ 45 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON B8 · EXPLAINER

Relations and Functions: Notation, Composite and Inverse Functions

A function is a machine: put one number in, get exactly one number out. Composite and inverse functions are machines in a chain and machines running backwards.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Relation

Any set of ordered pairs. Domain = inputs; range = outputs used; co-domain = set of possible outputs; image = output for a given input.

Function

Each element of the domain has exactly one image. One-to-one and many-to-one are functions; one-to-many is not.

Tests

Arrow diagram: one arrow per input. Graph: vertical line test.

Notation

f(x) = …; f : x → …; y = f(x). f(a) means substitute a for x.

Composite

fg(x) = f(g(x)) — g acts first. In general fg ≠ gf.

Inverse

Swap x and y and solve for y. f f⁻¹(x) = x. Graph of f⁻¹ is the reflection of f in y = x.

Solving f(x) = k

Set the rule equal to k and solve.

Inverse of composite

(fg)⁻¹ = g⁻¹ f⁻¹.

EXAM TIPS & COMMON MISTAKES

  • fg(x) means g FIRST, then f — read it right to left.
  • When evaluating f(−2), put the negative in brackets: 2(−2) + 3.
  • To check an inverse, compute f(f⁻¹(x)); the answer must be x.
  • A relation fails the function test if one input has TWO outputs — an input may not repeat with different images.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

CSEC Paper 01 style · SO 3.5

1. Which of the following relations is NOT a function?

Answer: A. 1 is mapped to both 2 and 3.
Adapted from CSEC P1 May/June 2024 (range of f : x → x³)

2. The range of f : x → x³ for the domain {−2, −1, 0, 1, 2} is

Answer: B. Cubing: −8, −1, 0, 1, 8.
CSEC Paper 01 style · SO 3.14

3. If f(x) = 3x − 2, then f(4) is

Answer: B. 3(4) − 2 = 10.
CSEC Paper 01 style · SO 3.11

4. If f(x) = 2x − 1 and g(x) = x² + 3, then fg(x) is

Answer: C. f(x² + 3) = 2(x² + 3) − 1 = 2x² + 5.
CSEC Paper 01 style · SO 3.13

5. If f(x) = 2x + 3, then f⁻¹(x) is

Answer: D. x = 2y + 3 → y = (x − 3)/2.
CSEC Paper 01 style · SO 3.14

6. If f(x) = 2x + 1, then f⁻¹(5) is

Answer: A. f⁻¹(x) = (x − 1)/2; (5 − 1)/2 = 2.
CSEC Paper 01 style · SO 3.14

7. If g(x) = x² − 5, then g(−3) is

Answer: A. (−3)² − 5 = 9 − 5 = 4.
CSEC Paper 01 style · SO 3.11

8. For two functions f and g, which statement is generally true?

Answer: B. Composition is not commutative in general.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (18 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Module 2 (Functions)

Question 1 [9 marks]

The functions f and g are defined by f(x) = 3x − 4 and g(x) = x².

(a) Evaluate f(5). [1]

MARK SCHEME — (a) (max 1)

(b) Find an expression for f⁻¹(x). [2]

MARK SCHEME — (b) (max 2)

(c) Show that gf(x) = (3x − 4)² and write gf(x) in expanded form. [3]

MARK SCHEME — (c) (max 3)

(d) Solve gf(x) = 25. [3]

MARK SCHEME — (d) (max 3)

CSEC Paper 02 style · Module 2 (Relations and inverse functions)

Question 2 [9 marks]

A relation is given by the set of ordered pairs {(1, 4), (2, 5), (3, 6), (3, 7)}.

(a) State the domain and the range of the relation. [2]

MARK SCHEME — (a) (max 2)

(b) Is the relation a function? Give a reason. [2]

MARK SCHEME — (b) (max 2)

(c) The function h is defined by h(x) = 5 − 2x. Find h(−1), h⁻¹(x), and show that h h⁻¹(3) = 3. [5]

MARK SCHEME — (c) (max 5)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.