CSEC ADDITIONAL MATHEMATICS · SECTION 3 · LESSON C5

Stationary Points and Optimisation

Finding stationary points, deciding whether they are maxima or minima using sign changes or the second derivative, and solving maximum and minimum problems.

Introductory CalculusS3 A.13S3 A.14S3 A.15≈ 50 min🎮 3 games
Before you start

By the end of this lesson you can…

Step 1 · Watch

Explainer video

5 narrated scenes. Press play, listen and read along — the points appear as they are explained. Use ‹ Prev / Next › or the scene bar to jump to any scene.

LESSON C5 · EXPLAINER

Stationary Points and Optimisation

What size box holds the most? What shape of tin uses the least metal? Wherever you need a best answer, calculus finds it where the gradient is zero.

Narration uses your device’s built-in voice. No sound? Switch to “Captions only” — the captions advance on their own.

Explore in 3D

Stationary points and optimisation

Move along the curve, then build the open box of greatest volume.

Step 2 · Read

Key notes

Copy these into your notebook in your own words — that is how they stick.

Stationary point

dy/dx = 0; find x, then y from the curve.

Second derivative test

f″ < 0 maximum; f″ > 0 minimum; f″ = 0 inconclusive.

Sign test

+ → − maximum; − → + minimum.

Optimisation steps

Variables → quantity and constraint → one variable → derivative = 0 → nature → answer.

Domain

State the allowed values; check end-points if needed.

Answer

Give the value asked (volume, area, dimension) with units.

Cylinder

Minimum surface area for fixed V: h = 2r.

Check

Substitute back; compare with a value either side.

EXAM TIPS & COMMON MISTAKES

  • Find the y-coordinate of a stationary point from the original curve, not from dy/dx.
  • Always test the nature — do not assume a stationary point is a maximum.
  • Reject values outside the domain (e.g. x = 6 gives zero volume for the box).
  • Answer the question asked: “the maximum volume is 128 cm³ when x = 2 cm”.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play — your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Additional Mathematics Arcade.

Step 3 · Practise

Paper 1 practice — multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

CSEC Paper 01 style · SO A.13

1. The curve y = x³ − 6x² + 9x + 1 has stationary points at x equals

Answer: A. 3(x − 1)(x − 3) = 0.
CSEC Paper 01 style · SO A.15

2. At x = 1 on y = x³ − 6x² + 9x + 1, the second derivative is

Answer: B. 6x − 12 at x = 1.
Adapted from CSEC P1 May/June 2024 (nature of a stationary point item)

3. The curve C has a stationary point at (−1, 2). If f″(x) = 4x + 6, then (−1, 2) is

Answer: C. f″(−1) = 2 > 0.
CSEC Paper 01 style · SO A.14

4. A point where dy/dx changes from positive to negative is a

Answer: D. + → 0 → − is a maximum.
CSEC Paper 01 style · SO A.14

5. The maximum volume of the open box V = x(12 − 2x)² for 0 < x < 6 is

Answer: A. x = 2: 2 × 64.
CSEC Paper 01 style · SO A.14

6. A pen against a wall uses 60 m of fencing on three sides. Its area A = x(60 − 2x) is greatest when x equals

Answer: B. dA/dx = 60 − 4x = 0.
CSEC Paper 01 style · SO A.14

7. For a closed cylinder of fixed volume, the surface area is a minimum when the height h is related to the radius r by

Answer: B. dS/dr = 0 gives r³ = V/(2π), h = 2r.
CSEC Paper 01 style · SO A.15

8. If f″(x) = 0 at a stationary point, the second-derivative test is

Answer: C. Use the sign-change test.
Step 4 · Apply

Paper 2 practice — structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (22 marks in total). Show all your working — method marks count. Your answers are saved on this device.

CSEC Paper 02 style · Section 3 (Stationary points)

Question 1 [11 marks]

The curve C has equation y = x³ − 6x² + 9x + 1.

(a) Find dy/dx and the coordinates of the stationary points of C. [5]

MARK SCHEME — (a) (max 5)

(b) Determine the nature of each stationary point. [3]

MARK SCHEME — (b) (max 3)

(c) Sketch the curve for −1 ≤ x ≤ 4, showing the stationary points and the y-intercept. (Check: cubic shape; (0, 1) marked; maximum (1, 5); minimum (3, 1).) [3]

MARK SCHEME — (c) (max 3)

CSEC Paper 02 style · Section 3 (Optimisation)

Question 2 [11 marks]

An open box is made from a square sheet of card of side 12 cm by cutting a square of side x cm from each corner and folding up the sides.

(a) Show that the volume of the box is V = 4x³ − 48x² + 144x. [2]

MARK SCHEME — (a) (max 2)

(b) Find the value of x that makes V a maximum and justify your answer. [5]

MARK SCHEME — (b) (max 5)

(c) Find the maximum volume. [2]

MARK SCHEME — (c) (max 2)

(d) State the range of values of x for which the box can be made. [2]

MARK SCHEME — (d) (max 2)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.