CSEC ADDITIONAL MATHEMATICS ยท SECTION 2 ยท LESSON B1

Coordinate Geometry: Equations of Straight Lines

Equations of lines in any form, parallel and perpendicular gradients, intersection of two lines, midpoints, perpendicular bisectors and simple problems.

Coordinate Geometry, Vectors and TrigonometryS2 A.1S2 A.2S2 A.3โ‰ˆ 40 min๐ŸŽฎ 3 games
Before you start

By the end of this lesson you canโ€ฆ

Step 1 ยท Watch

Explainer video

5 narrated scenes. Press play, listen and read along โ€” the points appear as they are explained. Use โ€น Prev / Next โ€บ or the scene bar to jump to any scene.

LESSON B1 ยท EXPLAINER

Coordinate Geometry: Equations of Straight Lines

Two points define a line. From them you can write its equation, find its perpendicular, locate where it meets another line โ€” all with a few lines of algebra.

Narration uses your deviceโ€™s built-in voice. No sound? Switch to โ€œCaptions onlyโ€ โ€” the captions advance on their own.

Explore in 3D

Straight lines

Change the gradient and intercept; add a parallel or perpendicular line.

Step 2 ยท Read

Key notes

Copy these into your notebook in your own words โ€” that is how they stick.

Gradient

m = (yโ‚‚ โˆ’ yโ‚)/(xโ‚‚ โˆ’ xโ‚); from ax + by + c = 0, m = โˆ’a/b.

Equation

y โˆ’ yโ‚ = m(x โˆ’ xโ‚); or y = mx + c; or ax + by + c = 0.

Parallel

mโ‚ = mโ‚‚.

Perpendicular

mโ‚mโ‚‚ = โˆ’1.

Intersection

Solve the two equations simultaneously.

Midpoint

((xโ‚ + xโ‚‚)/2, (yโ‚ + yโ‚‚)/2).

Perpendicular bisector

Through the midpoint with the negative reciprocal gradient.

Collinear

Equal gradients between successive pairs of points.

EXAM TIPS & COMMON MISTAKES

  • Write the gradient first; then choose a point and use y โˆ’ yโ‚ = m(x โˆ’ xโ‚).
  • For perpendicular gradients flip AND change sign: 4/3 โ†’ โˆ’3/4.
  • Check your equation by substituting both original points.
  • Leave answers as fractions when exact; round only when asked.
Play & practise

Games

3 quick games on this lesson. Earn XP and badges as you play โ€” your best score for each game is saved. Games are for practice and do not change your exam readiness. More games in the Additional Mathematics Arcade.

Step 3 ยท Practise

Paper 1 practice โ€” multiple choice

8 items modelled on real CSEC Paper 1 questions. Choose one answer for each, then check. Aim for 80% or better. Work each item on paper first.

Adapted from CSEC P1 May/June 2024 (parallel lines item)

1. The line through Q(h, 2) and R(4, 8) is parallel to the line x + y โˆ’ 10 = 0. The value of h is

Answer: D. Gradient โˆ’1: 6/(4 โˆ’ h) = โˆ’1 โ†’ h = 10.
CSEC Paper 01 style ยท SO A.1

2. The gradient of the line through (2, 3) and (6, 11) is

Answer: A. 8/4 = 2.
CSEC Paper 01 style ยท SO A.1

3. The equation of the line through (2, 3) and (6, 11) is

Answer: B. y โˆ’ 3 = 2(x โˆ’ 2).
CSEC Paper 01 style ยท SO A.1

4. The gradient of 3x โˆ’ 2y + 6 = 0 is

Answer: C. y = (3/2)x + 3.
CSEC Paper 01 style ยท SO A.2

5. A line perpendicular to y = 2x โˆ’ 1 has gradient

Answer: D. 2 ร— (โˆ’ยฝ) = โˆ’1.
CSEC Paper 01 style ยท SO A.3

6. The lines y = 2x โˆ’ 1 and x + 2y = 9 intersect at

Answer: A. 5x = 11.
CSEC Paper 01 style ยท SO A.2

7. The perpendicular bisector of A(1, 2) and B(7, 10) has equation

Answer: B. Through (4, 6) with gradient โˆ’3/4.
CSEC Paper 01 style ยท SO A.3

8. Which set of points is collinear?

Answer: C. Gradients 2 and 2.
Step 4 ยท Apply

Paper 2 practice โ€” structured questions

Write full answers, then reveal the mark scheme and tick the points you earned (25 marks in total). Show all your working โ€” method marks count. Your answers are saved on this device.

CSEC Paper 02 style ยท Section 2 (Coordinate geometry)

Question 1 [13 marks]

The vertices of a triangle are A(1, 1), B(7, 3) and C(2, โˆ’2).

(a) Find the gradient of AB and the equation of AC. [4]

MARK SCHEME โ€” (a) (max 4)

(b) Show that angle BAC = 90ยฐ. [2]

MARK SCHEME โ€” (b) (max 2)

(c) Find the equation of the line through A parallel to BC. [3]

MARK SCHEME โ€” (c) (max 3)

(d) Calculate the area of triangle ABC. [4]

MARK SCHEME โ€” (d) (max 4)

CSEC Paper 02 style ยท Section 2 (Perpendicular bisector)

Question 2 [12 marks]

A(1, 2) and B(7, 10) are two points.

(a) Find the midpoint M of AB and the gradient of AB. [3]

MARK SCHEME โ€” (a) (max 3)

(b) Show that the perpendicular bisector of AB has equation 3x + 4y = 36. [3]

MARK SCHEME โ€” (b) (max 3)

(c) The perpendicular bisector meets the axes at P and Q. Find the area of triangle OPQ, where O is the origin. [4]

MARK SCHEME โ€” (c) (max 4)

(d) Show that C(10, 14) lies on the line AB. [2]

MARK SCHEME โ€” (d) (max 2)

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Sources

Where this topic appears in CSEC papers

Find these in your own past-paper booklets for extra timed practice. Items above are written in the style of these papers; any adapted from a specific question say so.